Difference between revisions of "Hyperoptimistic conjecture"
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Revision as of 01:19, 14 February 2009
Gil Kalai and Tim Gowers have proposed a “hyperoptimistic” conjecture. Given a set [math]A \subset {}[3]^n[/math], define the weighted size [math]\mu(A)[/math] of [math]A[/math] by the formula
 [math]\mu(A) := \sum_{a+b+c=n} A \cap \Gamma_{a,b,c}/\Gamma_{a,b,c}[/math]
thus each slice [math]\Gamma_{a,b,c}\lt\math\gt has weighted size 1 (and we have been referring to \mu as “slicesequal measure” for this reason), and the whole cube \ltmath\gt{}[3]^n\lt\math\gt has weighted size equal to the \ltmath\gt(n+1)^{th}\lt\math\gt triangular number, \ltmath\gt\frac{(n+1)(n+2)}{2}\lt\math\gt. '''Example:''' in \ltmath\gt{}[3]^2[/math], the diagonal points 11, 22, 33 each have weighted size 1, whereas the other six offdiagonal points have weighted size 1/2. The total weighted size of [math]{}[3]^2[/math] is 6.
Let [math]c^\mu_n[/math] be the largest weighted size of a linefree set. For instance, [math]c^\mu_0 = 1[/math], [math]c^\mu_1 = 2[/math], and [math]c^\mu_2 = 4[/math].
As in the unweighted case, every time we find a subset [math]B[/math] of the grid [math]\Delta_n := \{ (a,b,c): a+b+c=n\}[/math] without equilateral triangles, it gives a linefree set [math]\Gamma_B := \bigcup_{(a,b,c) \in B} \Gamma_{a,b,c}[/math]. The weighted size of this set is precisely the cardinality of B. Thus we have the lower bound [math]c^\mu_n \geq \overline{c}^\mu_n[/math], where [math]\overline{c}^\mu_n[/math] is the largest size of equilateral triangles in [math]\Delta_n[/math]. The computation of the [math]\overline{c}^\mu_n[/math] is Fujimura's problem.
Hyperoptimistic conjecture: We in fact have [math]c^\mu_n = \overline{c}^\mu_n[/math]. In other words, to get the optimal weighted size for a linefree set, one should take a set which is a union of slices [math]\Gamma_{a,b,c}[/math].
This conjecture, if true, will imply the DHJ theorem. Note also that all our best lower bounds for the unweighted problem to date have been unions of slices. Also, the k=2 analogue of the conjecture is true, and is known as the LYM inequality (in fact, for k=2 we have [math]c^\mu_n = \overline{c}^\mu_n = 1[/math] for all n).